Base | Representation |
---|---|
bin | 10000000010110101000… |
… | …00010011001010101011 |
3 | 1221200221020201111102111 |
4 | 20001122200103022223 |
5 | 33013002200333233 |
6 | 1101130223543151 |
7 | 54554042433556 |
oct | 10013240231253 |
9 | 1850836644374 |
10 | 551274230443 |
11 | 1a2880a27762 |
12 | 8aa1075aab7 |
13 | 3cca5ba21c1 |
14 | 1c978c8769d |
15 | e5172c7acd |
hex | 805a8132ab |
551274230443 has 2 divisors, whose sum is σ = 551274230444. Its totient is φ = 551274230442.
The previous prime is 551274230431. The next prime is 551274230447. The reversal of 551274230443 is 344032472155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 551274230443 - 25 = 551274230411 is a prime.
It is a super-3 number, since 3×5512742304433 (a number of 36 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 551274230396 and 551274230405.
It is not a weakly prime, because it can be changed into another prime (551274230447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275637115221 + 275637115222.
It is an arithmetic number, because the mean of its divisors is an integer number (275637115222).
Almost surely, 2551274230443 is an apocalyptic number.
551274230443 is a deficient number, since it is larger than the sum of its proper divisors (1).
551274230443 is an equidigital number, since it uses as much as digits as its factorization.
551274230443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 40.
The spelling of 551274230443 in words is "five hundred fifty-one billion, two hundred seventy-four million, two hundred thirty thousand, four hundred forty-three".
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