Base | Representation |
---|---|
bin | 11001000100011100010011… |
… | …00111011101010100001001 |
3 | 21020012012120000122210220111 |
4 | 30202032021213131110021 |
5 | 24211210040300111231 |
6 | 313125315114154321 |
7 | 14416611351650245 |
oct | 1442161147352411 |
9 | 236165500583814 |
10 | 55128214066441 |
11 | 1662482071842a |
12 | 62242734229a1 |
13 | 249b750685439 |
14 | d883111a5425 |
15 | 6590285194b1 |
hex | 3223899dd509 |
55128214066441 has 2 divisors, whose sum is σ = 55128214066442. Its totient is φ = 55128214066440.
The previous prime is 55128214066417. The next prime is 55128214066451. The reversal of 55128214066441 is 14466041282155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54759570800841 + 368643265600 = 7399971^2 + 607160^2 .
It is a cyclic number.
It is not a de Polignac number, because 55128214066441 - 239 = 54578458252553 is a prime.
It is not a weakly prime, because it can be changed into another prime (55128214066411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27564107033220 + 27564107033221.
It is an arithmetic number, because the mean of its divisors is an integer number (27564107033221).
Almost surely, 255128214066441 is an apocalyptic number.
It is an amenable number.
55128214066441 is a deficient number, since it is larger than the sum of its proper divisors (1).
55128214066441 is an equidigital number, since it uses as much as digits as its factorization.
55128214066441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1843200, while the sum is 49.
The spelling of 55128214066441 in words is "fifty-five trillion, one hundred twenty-eight billion, two hundred fourteen million, sixty-six thousand, four hundred forty-one".
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