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5513001052453 = 12810834303391
BaseRepresentation
bin101000000111001100001…
…1110000010100100100101
3201112001000112002201210221
41100032120132002210211
51210311111232134303
615420345425244341
71106205206521516
oct120163036024445
921461015081727
105513001052453
111836061409104
12750558a936b1
1330cb48891a8b
14150b8b52aa0d
15986149134bd
hex50398782925

5513001052453 has 4 divisors (see below), whose sum is σ = 5513006636928. Its totient is φ = 5512995467980.

The previous prime is 5513001052421. The next prime is 5513001052519. The reversal of 5513001052453 is 3542501003155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5513001052453 - 25 = 5513001052421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5513001082453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 870613 + ... + 3432778.

It is an arithmetic number, because the mean of its divisors is an integer number (1378251659232).

Almost surely, 25513001052453 is an apocalyptic number.

It is an amenable number.

5513001052453 is a deficient number, since it is larger than the sum of its proper divisors (5584475).

5513001052453 is a wasteful number, since it uses less digits than its factorization.

5513001052453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5584474.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 5513001052453 in words is "five trillion, five hundred thirteen billion, one million, fifty-two thousand, four hundred fifty-three".

Divisors: 1 1281083 4303391 5513001052453