Base | Representation |
---|---|
bin | 111110101011010100110011… |
… | …0000110011110001001101111 |
3 | 2200022000221102110011020001110 |
4 | 1331112221212012132021233 |
5 | 1034230200100041142201 |
6 | 5232313213154043103 |
7 | 224060666602260003 |
oct | 17526514606361157 |
9 | 2608027373136043 |
10 | 551312305021551 |
11 | 14a735265558947 |
12 | 51a00027579493 |
13 | 1a8816b15b1228 |
14 | 9a1d92d54a703 |
15 | 43b0d718a56d6 |
hex | 1f56a6619e26f |
551312305021551 has 32 divisors (see below), whose sum is σ = 803762869598208. Its totient is φ = 334624184248320.
The previous prime is 551312305021481. The next prime is 551312305021553. The reversal of 551312305021551 is 155120503213155.
It is not a de Polignac number, because 551312305021551 - 210 = 551312305020527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (551312305021553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68315905 + ... + 75958458.
It is an arithmetic number, because the mean of its divisors is an integer number (25117589674944).
Almost surely, 2551312305021551 is an apocalyptic number.
551312305021551 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
551312305021551 is a deficient number, since it is larger than the sum of its proper divisors (252450564576657).
551312305021551 is a wasteful number, since it uses less digits than its factorization.
551312305021551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 144276831.
The product of its (nonzero) digits is 112500, while the sum is 39.
The spelling of 551312305021551 in words is "five hundred fifty-one trillion, three hundred twelve billion, three hundred five million, twenty-one thousand, five hundred fifty-one".
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