Base | Representation |
---|---|
bin | 111110101011100011010011… |
… | …0001001100011100101110010 |
3 | 2200022010220210121021122211222 |
4 | 1331113012212021203211302 |
5 | 1034231202333222440104 |
6 | 5232335403125505042 |
7 | 224063151345163121 |
oct | 17527064611434562 |
9 | 2608126717248758 |
10 | 551343444343154 |
11 | 14a747494924081 |
12 | 51a06077b72182 |
13 | 1a884604a13b08 |
14 | 9a2124500bab8 |
15 | 43b1a955311be |
hex | 1f571a6263972 |
551343444343154 has 4 divisors (see below), whose sum is σ = 827015166514734. Its totient is φ = 275671722171576.
The previous prime is 551343444343039. The next prime is 551343444343163. The reversal of 551343444343154 is 451343444343155.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 539784974292529 + 11558470050625 = 23233273^2 + 3399775^2 .
It is a junction number, because it is equal to n+sod(n) for n = 551343444343096 and 551343444343105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 137835861085787 + ... + 137835861085790.
Almost surely, 2551343444343154 is an apocalyptic number.
551343444343154 is a deficient number, since it is larger than the sum of its proper divisors (275671722171580).
551343444343154 is a wasteful number, since it uses less digits than its factorization.
551343444343154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 275671722171579.
The product of its digits is 41472000, while the sum is 53.
Subtracting from 551343444343154 its reverse (451343444343155), we obtain a palindrome (99999999999999).
The spelling of 551343444343154 in words is "five hundred fifty-one trillion, three hundred forty-three billion, four hundred forty-four million, three hundred forty-three thousand, one hundred fifty-four".
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