Base | Representation |
---|---|
bin | 10000000010111110100… |
… | …10001111011100110011 |
3 | 1221201010211122010021222 |
4 | 20001133102033130303 |
5 | 33013133213300113 |
6 | 1101142210535255 |
7 | 54556035224345 |
oct | 10013722173463 |
9 | 1851124563258 |
10 | 551354431283 |
11 | 1a2912225847 |
12 | 8aa3359752b |
13 | 3ccb96a2b16 |
14 | 1c9857a3295 |
15 | e51e36ae08 |
hex | 805f48f733 |
551354431283 has 2 divisors, whose sum is σ = 551354431284. Its totient is φ = 551354431282.
The previous prime is 551354431247. The next prime is 551354431289. The reversal of 551354431283 is 382134453155.
551354431283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 551354431283 - 26 = 551354431219 is a prime.
It is not a weakly prime, because it can be changed into another prime (551354431289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275677215641 + 275677215642.
It is an arithmetic number, because the mean of its divisors is an integer number (275677215642).
Almost surely, 2551354431283 is an apocalyptic number.
551354431283 is a deficient number, since it is larger than the sum of its proper divisors (1).
551354431283 is an equidigital number, since it uses as much as digits as its factorization.
551354431283 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864000, while the sum is 44.
The spelling of 551354431283 in words is "five hundred fifty-one billion, three hundred fifty-four million, four hundred thirty-one thousand, two hundred eighty-three".
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