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551404405553 is a prime number
BaseRepresentation
bin10000000011000100100…
…00111000001100110001
31221201021022200002002212
420001202100320030301
533013234011434203
61101151154021505
754560213054051
oct10014220701461
91851238602085
10551404405553
111a29384591a1
128aa48277895
133ccc6b4c5b1
141c98c291561
15e52393d1d8
hex8062438331

551404405553 has 2 divisors, whose sum is σ = 551404405554. Its totient is φ = 551404405552.

The previous prime is 551404405549. The next prime is 551404405561. The reversal of 551404405553 is 355504404155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 361258698304 + 190145707249 = 601048^2 + 436057^2 .

It is a cyclic number.

It is not a de Polignac number, because 551404405553 - 22 = 551404405549 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 551404405553.

It is not a weakly prime, because it can be changed into another prime (551404405523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275702202776 + 275702202777.

It is an arithmetic number, because the mean of its divisors is an integer number (275702202777).

Almost surely, 2551404405553 is an apocalyptic number.

It is an amenable number.

551404405553 is a deficient number, since it is larger than the sum of its proper divisors (1).

551404405553 is an equidigital number, since it uses as much as digits as its factorization.

551404405553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 600000, while the sum is 41.

The spelling of 551404405553 in words is "five hundred fifty-one billion, four hundred four million, four hundred five thousand, five hundred fifty-three".