Base | Representation |
---|---|
bin | 101000001000000111110… |
… | …0011111010000011110001 |
3 | 201112020011202202000011211 |
4 | 1100100033203322003301 |
5 | 1210324204231013103 |
6 | 15421320002040121 |
7 | 1106305550464324 |
oct | 120201743720361 |
9 | 21466152660154 |
10 | 5514999079153 |
11 | 1836997228143 |
12 | 750a16049041 |
13 | 3100a67c7bb5 |
14 | 150cdaa307bb |
15 | 986d003636d |
hex | 5040f8fa0f1 |
5514999079153 has 2 divisors, whose sum is σ = 5514999079154. Its totient is φ = 5514999079152.
The previous prime is 5514999079127. The next prime is 5514999079201. The reversal of 5514999079153 is 3519709994155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4133544404544 + 1381454674609 = 2033112^2 + 1175353^2 .
It is a cyclic number.
It is not a de Polignac number, because 5514999079153 - 213 = 5514999070961 is a prime.
It is not a weakly prime, because it can be changed into another prime (5514999079553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757499539576 + 2757499539577.
It is an arithmetic number, because the mean of its divisors is an integer number (2757499539577).
Almost surely, 25514999079153 is an apocalyptic number.
It is an amenable number.
5514999079153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5514999079153 is an equidigital number, since it uses as much as digits as its factorization.
5514999079153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68890500, while the sum is 67.
The spelling of 5514999079153 in words is "five trillion, five hundred fourteen billion, nine hundred ninety-nine million, seventy-nine thousand, one hundred fifty-three".
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