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55150210505347 is a prime number
BaseRepresentation
bin11001000101000101010001…
…01101001101101010000011
321020021022022222211200110221
430202202220231031222003
524212040112342132342
6313143353522203511
714421320425414606
oct1442425055155203
9236238288750427
1055150210505347
1116633089081561
126228591ab3597
1324a084785b569
14d893da69a33d
156598b4692a67
hex3228a8b4da83

55150210505347 has 2 divisors, whose sum is σ = 55150210505348. Its totient is φ = 55150210505346.

The previous prime is 55150210505197. The next prime is 55150210505413. The reversal of 55150210505347 is 74350501205155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55150210505347 - 235 = 55115850766979 is a prime.

It is a super-4 number, since 4×551502105053474 (a number of 56 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (55150210545347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27575105252673 + 27575105252674.

It is an arithmetic number, because the mean of its divisors is an integer number (27575105252674).

Almost surely, 255150210505347 is an apocalyptic number.

55150210505347 is a deficient number, since it is larger than the sum of its proper divisors (1).

55150210505347 is an equidigital number, since it uses as much as digits as its factorization.

55150210505347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 525000, while the sum is 43.

The spelling of 55150210505347 in words is "fifty-five trillion, one hundred fifty billion, two hundred ten million, five hundred five thousand, three hundred forty-seven".