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551503004113 is a prime number
BaseRepresentation
bin10000000011010000010…
…01000000000111010001
31221201112012012101220101
420001220021000013101
533013434232112423
61101205035212401
754562521121315
oct10015011000721
91851465171811
10551503004113
111a2989082806
128aa752a7101
13400113c2239
141c99b3d9b45
15e52c4177ad
hex80682401d1

551503004113 has 2 divisors, whose sum is σ = 551503004114. Its totient is φ = 551503004112.

The previous prime is 551503004099. The next prime is 551503004153. The reversal of 551503004113 is 311400305155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 524795927184 + 26707076929 = 724428^2 + 163423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551503004113 is a prime.

It is not a weakly prime, because it can be changed into another prime (551503004153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275751502056 + 275751502057.

It is an arithmetic number, because the mean of its divisors is an integer number (275751502057).

Almost surely, 2551503004113 is an apocalyptic number.

It is an amenable number.

551503004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

551503004113 is an equidigital number, since it uses as much as digits as its factorization.

551503004113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 551503004113 its reverse (311400305155), we get a palindrome (862903309268).

The spelling of 551503004113 in words is "five hundred fifty-one billion, five hundred three million, four thousand, one hundred thirteen".