Base | Representation |
---|---|
bin | 101000001000001100011… |
… | …0111100010101010001011 |
3 | 201112020120122112211201001 |
4 | 1100100120313202222023 |
5 | 1210330014214034011 |
6 | 15421343300435431 |
7 | 1106312454614623 |
oct | 120203067425213 |
9 | 21466518484631 |
10 | 5515155221131 |
11 | 1836a673849a6 |
12 | 750a5a3a8b77 |
13 | 3100ccc675ba |
14 | 150d13677883 |
15 | 986ddaca7c1 |
hex | 50418de2a8b |
5515155221131 has 2 divisors, whose sum is σ = 5515155221132. Its totient is φ = 5515155221130.
The previous prime is 5515155221101. The next prime is 5515155221167. The reversal of 5515155221131 is 1311225515155.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5515155221131 - 25 = 5515155221099 is a prime.
It is a super-2 number, since 2×55151552211312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5515155221101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757577610565 + 2757577610566.
It is an arithmetic number, because the mean of its divisors is an integer number (2757577610566).
Almost surely, 25515155221131 is an apocalyptic number.
5515155221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5515155221131 is an equidigital number, since it uses as much as digits as its factorization.
5515155221131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 37500, while the sum is 37.
The spelling of 5515155221131 in words is "five trillion, five hundred fifteen billion, one hundred fifty-five million, two hundred twenty-one thousand, one hundred thirty-one".
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