Base | Representation |
---|---|
bin | 11001000101001000110110… |
… | …11011010101110101100111 |
3 | 21020021111022010111022022220 |
4 | 30202210123123111311213 |
5 | 24212103033102400403 |
6 | 313144312515123423 |
7 | 14421416216145564 |
oct | 1442443333256547 |
9 | 236244263438286 |
10 | 55152135200103 |
11 | 16633986564187 |
12 | 6228a2a5a3573 |
13 | 24a0a9352a3b6 |
14 | d8954015186b |
15 | 65997862c953 |
hex | 32291b6d5d67 |
55152135200103 has 8 divisors (see below), whose sum is σ = 73547150930688. Its totient is φ = 36762604801464.
The previous prime is 55152135200039. The next prime is 55152135200147. The reversal of 55152135200103 is 30100253125155.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55152135200103 - 26 = 55152135200039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55152135200153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1371309525 + ... + 1371349742.
It is an arithmetic number, because the mean of its divisors is an integer number (9193393866336).
Almost surely, 255152135200103 is an apocalyptic number.
55152135200103 is a deficient number, since it is larger than the sum of its proper divisors (18395015730585).
55152135200103 is a wasteful number, since it uses less digits than its factorization.
55152135200103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2742665973.
The product of its (nonzero) digits is 22500, while the sum is 33.
Adding to 55152135200103 its reverse (30100253125155), we get a palindrome (85252388325258).
The spelling of 55152135200103 in words is "fifty-five trillion, one hundred fifty-two billion, one hundred thirty-five million, two hundred thousand, one hundred three".
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