Base | Representation |
---|---|
bin | 11001000101011010100111… |
… | …00000111001110010000001 |
3 | 21020022101220100121001001021 |
4 | 30202231103200321302001 |
5 | 24212232043011213422 |
6 | 313152530343505441 |
7 | 14422204336460545 |
oct | 1442552340716201 |
9 | 236271810531037 |
10 | 55161666116737 |
11 | 16637a27508994 |
12 | 622a84a458281 |
13 | 24a1951c98a3b |
14 | d89ba5c89a25 |
15 | 659d3522cdc7 |
hex | 322b53839c81 |
55161666116737 has 2 divisors, whose sum is σ = 55161666116738. Its totient is φ = 55161666116736.
The previous prime is 55161666116663. The next prime is 55161666116759. The reversal of 55161666116737 is 73761166616155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31013326619521 + 24148339497216 = 5568961^2 + 4914096^2 .
It is a cyclic number.
It is not a de Polignac number, because 55161666116737 - 215 = 55161666083969 is a prime.
It is not a weakly prime, because it can be changed into another prime (55161666119737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27580833058368 + 27580833058369.
It is an arithmetic number, because the mean of its divisors is an integer number (27580833058369).
Almost surely, 255161666116737 is an apocalyptic number.
It is an amenable number.
55161666116737 is a deficient number, since it is larger than the sum of its proper divisors (1).
55161666116737 is an equidigital number, since it uses as much as digits as its factorization.
55161666116737 is an evil number, because the sum of its binary digits is even.
The product of its digits is 28576800, while the sum is 61.
The spelling of 55161666116737 in words is "fifty-five trillion, one hundred sixty-one billion, six hundred sixty-six million, one hundred sixteen thousand, seven hundred thirty-seven".
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