Base | Representation |
---|---|
bin | 111110101101101101100100… |
… | …0000010100000110101111001 |
3 | 2200100012022012120010200000121 |
4 | 1331123123020002200311321 |
5 | 1034301033432102300112 |
6 | 5233124030244133241 |
7 | 224123462340605362 |
oct | 17533331002406571 |
9 | 2610168176120017 |
10 | 551640365665657 |
11 | 14a851402202404 |
12 | 51a53722397221 |
13 | 1a8a6603a71a58 |
14 | 9a31771306b69 |
15 | 43b96727a9407 |
hex | 1f5b6c80a0d79 |
551640365665657 has 2 divisors, whose sum is σ = 551640365665658. Its totient is φ = 551640365665656.
The previous prime is 551640365665561. The next prime is 551640365665673. The reversal of 551640365665657 is 756566563046155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 335037001728256 + 216603363937401 = 18304016^2 + 14717451^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551640365665657 is a prime.
It is not a weakly prime, because it can be changed into another prime (551640365665687) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275820182832828 + 275820182832829.
It is an arithmetic number, because the mean of its divisors is an integer number (275820182832829).
Almost surely, 2551640365665657 is an apocalyptic number.
It is an amenable number.
551640365665657 is a deficient number, since it is larger than the sum of its proper divisors (1).
551640365665657 is an equidigital number, since it uses as much as digits as its factorization.
551640365665657 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2041200000, while the sum is 70.
The spelling of 551640365665657 in words is "five hundred fifty-one trillion, six hundred forty billion, three hundred sixty-five million, six hundred sixty-five thousand, six hundred fifty-seven".
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