Base | Representation |
---|---|
bin | 110011011001111010… |
… | …011010000001010001 |
3 | 12021110200012200202121 |
4 | 303121322122001101 |
5 | 1401020031334403 |
6 | 41205000414241 |
7 | 3662540432563 |
oct | 633172320121 |
9 | 167420180677 |
10 | 55195574353 |
11 | 2145450aa57 |
12 | a844a77381 |
13 | 528829638a |
14 | 2958781333 |
15 | 1680a7e3bd |
hex | cd9e9a051 |
55195574353 has 2 divisors, whose sum is σ = 55195574354. Its totient is φ = 55195574352.
The previous prime is 55195574321. The next prime is 55195574383. The reversal of 55195574353 is 35347559155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47658382864 + 7537191489 = 218308^2 + 86817^2 .
It is a cyclic number.
It is not a de Polignac number, because 55195574353 - 25 = 55195574321 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55195574353.
It is not a weakly prime, because it can be changed into another prime (55195574383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27597787176 + 27597787177.
It is an arithmetic number, because the mean of its divisors is an integer number (27597787177).
Almost surely, 255195574353 is an apocalyptic number.
It is an amenable number.
55195574353 is a deficient number, since it is larger than the sum of its proper divisors (1).
55195574353 is an equidigital number, since it uses as much as digits as its factorization.
55195574353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7087500, while the sum is 52.
The spelling of 55195574353 in words is "fifty-five billion, one hundred ninety-five million, five hundred seventy-four thousand, three hundred fifty-three".
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