5520131 has 2 divisors, whose sum is σ = 5520132. Its totient is φ = 5520130.

The previous prime is 5520113. The next prime is 5520157. The reversal of 5520131 is 1310255.

Together with previous prime (5520113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5520131 is a prime.

It is a super-2 number, since 2×5520131² = 60943692514322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5520101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2760065 + 2760066.

It is an arithmetic number, because the mean of its divisors is an integer number (2760066).

Almost surely, 2^5520131 is an apocalyptic number.

5520131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5520131 is an equidigital number, since it uses as much as digits as its factorization.

5520131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 5520131 is about 2349.4959033801. The cubic root of 5520131 is about 176.7325164912.

Adding to 5520131 its reverse (1310255), we get a palindrome (6830386).

The spelling of 5520131 in words is "five million, five hundred twenty thousand, one hundred thirty-one".