Base | Representation |
---|---|
bin | 11001000110110111001010… |
… | …00011111111010111100001 |
3 | 21020111011011002120111211122 |
4 | 30203123211003333113201 |
5 | 24214040322234314413 |
6 | 313231424550422025 |
7 | 14425613534161652 |
oct | 1443334503772741 |
9 | 236434132514748 |
10 | 55211352651233 |
11 | 1665700423a739 |
12 | 62383b6361915 |
13 | 24a653cb048cc |
14 | d8c35aadd529 |
15 | 65b292304108 |
hex | 3236e50ff5e1 |
55211352651233 has 2 divisors, whose sum is σ = 55211352651234. Its totient is φ = 55211352651232.
The previous prime is 55211352651209. The next prime is 55211352651241. The reversal of 55211352651233 is 33215625311255.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54350851523809 + 860501127424 = 7372303^2 + 927632^2 .
It is a cyclic number.
It is not a de Polignac number, because 55211352651233 - 232 = 55207057683937 is a prime.
It is not a weakly prime, because it can be changed into another prime (55211352656233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27605676325616 + 27605676325617.
It is an arithmetic number, because the mean of its divisors is an integer number (27605676325617).
Almost surely, 255211352651233 is an apocalyptic number.
It is an amenable number.
55211352651233 is a deficient number, since it is larger than the sum of its proper divisors (1).
55211352651233 is an equidigital number, since it uses as much as digits as its factorization.
55211352651233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 810000, while the sum is 44.
Adding to 55211352651233 its reverse (33215625311255), we get a palindrome (88426977962488).
The spelling of 55211352651233 in words is "fifty-five trillion, two hundred eleven billion, three hundred fifty-two million, six hundred fifty-one thousand, two hundred thirty-three".
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