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55212015301 = 107516000143
BaseRepresentation
bin110011011010111001…
…000111111011000101
312021111211010222111121
4303122321013323011
51401033233442201
641210345033541
73663130246432
oct633271077305
9167454128447
1055212015301
112146281a313
12a84a4858b1
13528b801851
14295aa20b89
15168222a9a1
hexcdae47ec5

55212015301 has 4 divisors (see below), whose sum is σ = 55728015552. Its totient is φ = 54696015052.

The previous prime is 55212015253. The next prime is 55212015329. The reversal of 55212015301 is 10351021255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55212015301 - 217 = 55211884229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55212015401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257999965 + ... + 258000178.

It is an arithmetic number, because the mean of its divisors is an integer number (13932003888).

Almost surely, 255212015301 is an apocalyptic number.

It is an amenable number.

55212015301 is a deficient number, since it is larger than the sum of its proper divisors (516000251).

55212015301 is a wasteful number, since it uses less digits than its factorization.

55212015301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 516000250.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 55212015301 its reverse (10351021255), we get a palindrome (65563036556).

The spelling of 55212015301 in words is "fifty-five billion, two hundred twelve million, fifteen thousand, three hundred one".

Divisors: 1 107 516000143 55212015301