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552120404021255 = 51794777912911411
BaseRepresentation
bin111110110001001101000110…
…0100011100001000000000111
32200101220012021020222210000002
41331202122030203201000013
51034331420041412140010
65234132340112111515
7224203245211400036
oct17542321443410007
92611805236883002
10552120404021255
1114aa16a48358a23
1251b1077223559b
131a90c966454104
149a4aaad38a71d
1543c6dbabeb1a5
hex1f6268c8e1007

552120404021255 has 16 divisors (see below), whose sum is σ = 666259846588800. Its totient is φ = 439219519049760.

The previous prime is 552120404021119. The next prime is 552120404021269.

552120404021255 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 552120404021255 - 210 = 552120404020231 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36306500 + ... + 49217910.

It is an arithmetic number, because the mean of its divisors is an integer number (41641240411800).

Almost surely, 2552120404021255 is an apocalyptic number.

552120404021255 is a deficient number, since it is larger than the sum of its proper divisors (114139442567545).

552120404021255 is a wasteful number, since it uses less digits than its factorization.

552120404021255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12959374.

The product of its (nonzero) digits is 160000, while the sum is 38.

It can be divided in two parts, 55212040 and 4021255, that added together give a palindrome (59233295).

The spelling of 552120404021255 in words is "five hundred fifty-two trillion, one hundred twenty billion, four hundred four million, twenty-one thousand, two hundred fifty-five".

Divisors: 1 5 179 895 47779 238895 8552441 12911411 42762205 64557055 2311142569 11555712845 616894306169 3084471530845 110424080804251 552120404021255