Base | Representation |
---|---|
bin | 111110110001001101000110… |
… | …0100011100001000000000111 |
3 | 2200101220012021020222210000002 |
4 | 1331202122030203201000013 |
5 | 1034331420041412140010 |
6 | 5234132340112111515 |
7 | 224203245211400036 |
oct | 17542321443410007 |
9 | 2611805236883002 |
10 | 552120404021255 |
11 | 14aa16a48358a23 |
12 | 51b1077223559b |
13 | 1a90c966454104 |
14 | 9a4aaad38a71d |
15 | 43c6dbabeb1a5 |
hex | 1f6268c8e1007 |
552120404021255 has 16 divisors (see below), whose sum is σ = 666259846588800. Its totient is φ = 439219519049760.
The previous prime is 552120404021119. The next prime is 552120404021269.
552120404021255 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 552120404021255 - 210 = 552120404020231 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36306500 + ... + 49217910.
It is an arithmetic number, because the mean of its divisors is an integer number (41641240411800).
Almost surely, 2552120404021255 is an apocalyptic number.
552120404021255 is a deficient number, since it is larger than the sum of its proper divisors (114139442567545).
552120404021255 is a wasteful number, since it uses less digits than its factorization.
552120404021255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12959374.
The product of its (nonzero) digits is 160000, while the sum is 38.
It can be divided in two parts, 55212040 and 4021255, that added together give a palindrome (59233295).
The spelling of 552120404021255 in words is "five hundred fifty-two trillion, one hundred twenty billion, four hundred four million, twenty-one thousand, two hundred fifty-five".
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