Base | Representation |
---|---|
bin | 110011011011000000… |
… | …110100110011010011 |
3 | 12021111221221112211002 |
4 | 303123000310303103 |
5 | 1401034243043011 |
6 | 41210500212215 |
7 | 3663153355304 |
oct | 633300646323 |
9 | 167457845732 |
10 | 55214034131 |
11 | 21463979073 |
12 | a84b09a06b |
13 | 528c05a719 |
14 | 295adc87ab |
15 | 16824c8c3b |
hex | cdb034cd3 |
55214034131 has 2 divisors, whose sum is σ = 55214034132. Its totient is φ = 55214034130.
The previous prime is 55214034121. The next prime is 55214034149. The reversal of 55214034131 is 13143041255.
55214034131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55214034131 is a prime.
It is a super-2 number, since 2×552140341312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55214034094 and 55214034103.
It is not a weakly prime, because it can be changed into another prime (55214034121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27607017065 + 27607017066.
It is an arithmetic number, because the mean of its divisors is an integer number (27607017066).
Almost surely, 255214034131 is an apocalyptic number.
55214034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
55214034131 is an equidigital number, since it uses as much as digits as its factorization.
55214034131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 55214034131 its reverse (13143041255), we get a palindrome (68357075386).
The spelling of 55214034131 in words is "fifty-five billion, two hundred fourteen million, thirty-four thousand, one hundred thirty-one".
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