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552214311331 is a prime number
BaseRepresentation
bin10000000100100101000…
…10011011000110100011
31221210100202122112222011
420002102202123012203
533021413330430311
61101403405053351
754616246125304
oct10022242330643
91853322575864
10552214311331
111a3213645411
128b033557257
13400c5890197
141ca27a787ab
15e56eac0321
hex809289b1a3

552214311331 has 2 divisors, whose sum is σ = 552214311332. Its totient is φ = 552214311330.

The previous prime is 552214311307. The next prime is 552214311353. The reversal of 552214311331 is 133113412255.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 552214311331 - 27 = 552214311203 is a prime.

It is a super-2 number, since 2×5522143113312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 552214311293 and 552214311302.

It is not a weakly prime, because it can be changed into another prime (552214311371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276107155665 + 276107155666.

It is an arithmetic number, because the mean of its divisors is an integer number (276107155666).

Almost surely, 2552214311331 is an apocalyptic number.

552214311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

552214311331 is an equidigital number, since it uses as much as digits as its factorization.

552214311331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10800, while the sum is 31.

Adding to 552214311331 its reverse (133113412255), we get a palindrome (685327723586).

The spelling of 552214311331 in words is "five hundred fifty-two billion, two hundred fourteen million, three hundred eleven thousand, three hundred thirty-one".