Base | Representation |
---|---|
bin | 11001000111011010100000… |
… | …11000010101010001011011 |
3 | 21020112222010212110220022022 |
4 | 30203231100120111101123 |
5 | 24214343210222441011 |
6 | 313244244213445055 |
7 | 14430155065462601 |
oct | 1443552030252133 |
9 | 236488125426268 |
10 | 55230333015131 |
11 | 16664064153a9a |
12 | 624001294078b |
13 | 24a8276188771 |
14 | d8d23b805871 |
15 | 65ba037b08db |
hex | 323b5061545b |
55230333015131 has 2 divisors, whose sum is σ = 55230333015132. Its totient is φ = 55230333015130.
The previous prime is 55230333015073. The next prime is 55230333015211. The reversal of 55230333015131 is 13151033303255.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55230333015131 - 226 = 55230265906267 is a prime.
It is a super-2 number, since 2×552303330151312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55230333015091 and 55230333015100.
It is not a weakly prime, because it can be changed into another prime (55230333015631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27615166507565 + 27615166507566.
It is an arithmetic number, because the mean of its divisors is an integer number (27615166507566).
Almost surely, 255230333015131 is an apocalyptic number.
55230333015131 is a deficient number, since it is larger than the sum of its proper divisors (1).
55230333015131 is an equidigital number, since it uses as much as digits as its factorization.
55230333015131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60750, while the sum is 35.
Adding to 55230333015131 its reverse (13151033303255), we get a palindrome (68381366318386).
The spelling of 55230333015131 in words is "fifty-five trillion, two hundred thirty billion, three hundred thirty-three million, fifteen thousand, one hundred thirty-one".
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