Base | Representation |
---|---|
bin | 11001000111100000011110… |
… | …00100000000011010001011 |
3 | 21020120021101211012000211021 |
4 | 30203300033010000122023 |
5 | 24214421233211310201 |
6 | 313245533454013311 |
7 | 14430330262526044 |
oct | 1443601704003213 |
9 | 236507354160737 |
10 | 55233532135051 |
11 | 16665455a56156 |
12 | 62407661a7237 |
13 | 24a8665ba982a |
14 | d8d4626418cb |
15 | 65bb3e587ea1 |
hex | 323c0f10068b |
55233532135051 has 2 divisors, whose sum is σ = 55233532135052. Its totient is φ = 55233532135050.
The previous prime is 55233532134967. The next prime is 55233532135073. The reversal of 55233532135051 is 15053123533255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55233532135051 - 215 = 55233532102283 is a prime.
It is a super-2 number, since 2×552335321350512 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55233532134989 and 55233532135007.
It is not a weakly prime, because it can be changed into another prime (55233532135151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27616766067525 + 27616766067526.
It is an arithmetic number, because the mean of its divisors is an integer number (27616766067526).
Almost surely, 255233532135051 is an apocalyptic number.
55233532135051 is a deficient number, since it is larger than the sum of its proper divisors (1).
55233532135051 is an equidigital number, since it uses as much as digits as its factorization.
55233532135051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1012500, while the sum is 43.
The spelling of 55233532135051 in words is "fifty-five trillion, two hundred thirty-three billion, five hundred thirty-two million, one hundred thirty-five thousand, fifty-one".
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