Base | Representation |
---|---|
bin | 101000001100000001000… |
… | …0011000101001110100011 |
3 | 201120000202121121220011201 |
4 | 1100120002003011032203 |
5 | 1210443321222224211 |
6 | 15425221515022031 |
7 | 1110023031644632 |
oct | 120300203051643 |
9 | 21500677556151 |
10 | 5523362304931 |
11 | 183a499033489 |
12 | 75256aa3a917 |
13 | 310b0a3750c3 |
14 | 151491649519 |
15 | 98a1e37e0c1 |
hex | 506020c53a3 |
5523362304931 has 2 divisors, whose sum is σ = 5523362304932. Its totient is φ = 5523362304930.
The previous prime is 5523362304907. The next prime is 5523362304953. The reversal of 5523362304931 is 1394032633255.
5523362304931 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5523362304931 - 211 = 5523362302883 is a prime.
It is a super-2 number, since 2×55233623049312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5523362305931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2761681152465 + 2761681152466.
It is an arithmetic number, because the mean of its divisors is an integer number (2761681152466).
Almost surely, 25523362304931 is an apocalyptic number.
5523362304931 is a deficient number, since it is larger than the sum of its proper divisors (1).
5523362304931 is an equidigital number, since it uses as much as digits as its factorization.
5523362304931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1749600, while the sum is 46.
The spelling of 5523362304931 in words is "five trillion, five hundred twenty-three billion, three hundred sixty-two million, three hundred four thousand, nine hundred thirty-one".
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