Search a number
-
+
552354041713 is a prime number
BaseRepresentation
bin10000000100110101101…
…11011100111101110001
31221210201111120121000111
420002122313130331301
533022210113313323
61101425320021321
754622563613435
oct10023267347561
91853644517014
10552354041713
111a3285502971
128b072301841
1340118804896
141ca3c44c9c5
15e57bec1c0d
hex809addcf71

552354041713 has 2 divisors, whose sum is σ = 552354041714. Its totient is φ = 552354041712.

The previous prime is 552354041699. The next prime is 552354041741. The reversal of 552354041713 is 317140453255.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 528627876624 + 23726165089 = 727068^2 + 154033^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-552354041713 is a prime.

It is a super-4 number, since 4×5523540417134 (a number of 48 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (559354041713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276177020856 + 276177020857.

It is an arithmetic number, because the mean of its divisors is an integer number (276177020857).

Almost surely, 2552354041713 is an apocalyptic number.

It is an amenable number.

552354041713 is a deficient number, since it is larger than the sum of its proper divisors (1).

552354041713 is an equidigital number, since it uses as much as digits as its factorization.

552354041713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252000, while the sum is 40.

Adding to 552354041713 its reverse (317140453255), we get a palindrome (869494494968).

The spelling of 552354041713 in words is "five hundred fifty-two billion, three hundred fifty-four million, forty-one thousand, seven hundred thirteen".