Base | Representation |
---|---|
bin | 111110110011011110110000… |
… | …0111000110010000011101100 |
3 | 2200110000002122211100200001111 |
4 | 1331212331200320302003230 |
5 | 1034402031200211324434 |
6 | 5234532151013321404 |
7 | 224234660533421443 |
oct | 17546754070620354 |
9 | 2613002584320044 |
10 | 552433204011244 |
11 | 150027673840146 |
12 | 51b6130a336264 |
13 | 1a9332c609599a |
14 | 9a5bca4471d5a |
15 | 43d00c6e9e964 |
hex | 1f66f60e320ec |
552433204011244 has 24 divisors (see below), whose sum is σ = 978589198918800. Its totient is φ = 272851083523776.
The previous prime is 552433204011239. The next prime is 552433204011259. The reversal of 552433204011244 is 442110402334255.
It is a junction number, because it is equal to n+sod(n) for n = 552433204011197 and 552433204011206.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1849036567 + ... + 1849335310.
It is an arithmetic number, because the mean of its divisors is an integer number (40774549954950).
Almost surely, 2552433204011244 is an apocalyptic number.
It is an amenable number.
552433204011244 is a deficient number, since it is larger than the sum of its proper divisors (426155994907556).
552433204011244 is a wasteful number, since it uses less digits than its factorization.
552433204011244 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3698372337 (or 3698372335 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 552433204011244 its reverse (442110402334255), we get a palindrome (994543606345499).
The spelling of 552433204011244 in words is "five hundred fifty-two trillion, four hundred thirty-three billion, two hundred four million, eleven thousand, two hundred forty-four".
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