Base | Representation |
---|---|
bin | 111110110011100011100100… |
… | …0011001111110010100010011 |
3 | 2200110001002022111211210222022 |
4 | 1331213013020121332110103 |
5 | 1034402213322324400201 |
6 | 5234541015430202055 |
7 | 224235504456011054 |
oct | 17547071031762423 |
9 | 2613032274753868 |
10 | 552443530700051 |
11 | 150030a929a8301 |
12 | 51b633107b332b |
13 | 1a934280666a33 |
14 | 9a5c5a3b5472b |
15 | 43d04cd88e41b |
hex | 1f671c867e513 |
552443530700051 has 2 divisors, whose sum is σ = 552443530700052. Its totient is φ = 552443530700050.
The previous prime is 552443530699937. The next prime is 552443530700077. The reversal of 552443530700051 is 150007035344255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 552443530700051 - 222 = 552443526505747 is a prime.
It is a super-2 number, since 2×5524435307000512 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 552443530699975 and 552443530700011.
It is not a weakly prime, because it can be changed into another prime (552443530700081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276221765350025 + 276221765350026.
It is an arithmetic number, because the mean of its divisors is an integer number (276221765350026).
Almost surely, 2552443530700051 is an apocalyptic number.
552443530700051 is a deficient number, since it is larger than the sum of its proper divisors (1).
552443530700051 is an equidigital number, since it uses as much as digits as its factorization.
552443530700051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260000, while the sum is 44.
The spelling of 552443530700051 in words is "five hundred fifty-two trillion, four hundred forty-three billion, five hundred thirty million, seven hundred thousand, fifty-one".
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