Base | Representation |
---|---|
bin | 11001000111111111001111… |
… | …00111100111111111000011 |
3 | 21020121212000222221100110212 |
4 | 30203333213213213333003 |
5 | 24220204100331041424 |
6 | 313301304522344335 |
7 | 14431453515312416 |
oct | 1443774747477703 |
9 | 236555028840425 |
10 | 55250050252739 |
11 | 16671462002491 |
12 | 62439b605b0ab |
13 | 24aa0990bc574 |
14 | d9018c323b7d |
15 | 65c2a97c510e |
hex | 323fe79e7fc3 |
55250050252739 has 2 divisors, whose sum is σ = 55250050252740. Its totient is φ = 55250050252738.
The previous prime is 55250050252723. The next prime is 55250050252753. The reversal of 55250050252739 is 93725205005255.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55250050252739 - 24 = 55250050252723 is a prime.
It is a super-3 number, since 3×552500502527393 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (55250050252759) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27625025126369 + 27625025126370.
It is an arithmetic number, because the mean of its divisors is an integer number (27625025126370).
Almost surely, 255250050252739 is an apocalyptic number.
55250050252739 is a deficient number, since it is larger than the sum of its proper divisors (1).
55250050252739 is an equidigital number, since it uses as much as digits as its factorization.
55250050252739 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4725000, while the sum is 50.
The spelling of 55250050252739 in words is "fifty-five trillion, two hundred fifty billion, fifty million, two hundred fifty-two thousand, seven hundred thirty-nine".
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