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5525005280503 = 53104245382651
BaseRepresentation
bin101000001100110001111…
…1110100010010011110111
3201120012000010011200221211
41100121203332202103313
51211010202322434003
615430052525422251
71110111532005112
oct120314376422367
921505003150854
105525005280503
111840161498335
1275294910a987
1331100c876bb7
141515a9929579
1598ab871b96d
hex50663fa24f7

5525005280503 has 4 divisors (see below), whose sum is σ = 5629250663208. Its totient is φ = 5420759897800.

The previous prime is 5525005280453. The next prime is 5525005280507. The reversal of 5525005280503 is 3050825005255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5525005280503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5525005280507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52122691273 + ... + 52122691378.

It is an arithmetic number, because the mean of its divisors is an integer number (1407312665802).

Almost surely, 25525005280503 is an apocalyptic number.

5525005280503 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

5525005280503 is a deficient number, since it is larger than the sum of its proper divisors (104245382705).

5525005280503 is a wasteful number, since it uses less digits than its factorization.

5525005280503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104245382704.

The product of its (nonzero) digits is 300000, while the sum is 40.

The spelling of 5525005280503 in words is "five trillion, five hundred twenty-five billion, five million, two hundred eighty thousand, five hundred three".

Divisors: 1 53 104245382651 5525005280503