Base | Representation |
---|---|
bin | 111110110100001001001110… |
… | …1010111101000001010010111 |
3 | 2200110022211002100020120102202 |
4 | 1331220102131113220022113 |
5 | 1034410024444214341401 |
6 | 5235042113343355115 |
7 | 224244400013412110 |
oct | 17550223527501227 |
9 | 2613284070216382 |
10 | 552524413043351 |
11 | 150062318976a21 |
12 | 51b76b23bb2a9b |
13 | 1a93baa0522578 |
14 | 9a62477b71207 |
15 | 43d266454d06b |
hex | 1f6849d5e8297 |
552524413043351 has 16 divisors (see below), whose sum is σ = 632200241046528. Its totient is φ = 473034792645600.
The previous prime is 552524413043329. The next prime is 552524413043353. The reversal of 552524413043351 is 153340314425255.
It is a cyclic number.
It is not a de Polignac number, because 552524413043351 - 234 = 552507233174167 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 552524413043296 and 552524413043305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (552524413043353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13936736 + ... + 36045546.
It is an arithmetic number, because the mean of its divisors is an integer number (39512515065408).
Almost surely, 2552524413043351 is an apocalyptic number.
552524413043351 is a deficient number, since it is larger than the sum of its proper divisors (79675828003177).
552524413043351 is a wasteful number, since it uses less digits than its factorization.
552524413043351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22113022.
The product of its (nonzero) digits is 4320000, while the sum is 47.
The spelling of 552524413043351 in words is "five hundred fifty-two trillion, five hundred twenty-four billion, four hundred thirteen million, forty-three thousand, three hundred fifty-one".
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