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55281009351 = 353813424457
BaseRepresentation
bin110011011111000000…
…010100001011000111
312021200121222020112210
4303133000110023013
51401203414244401
641221251514503
73664625553321
oct633700241307
9167617866483
1055281009351
1121498763597
12a8695b8a33
13529cbaa529
142965c60611
1516883084d6
hexcdf0142c7

55281009351 has 8 divisors (see below), whose sum is σ = 73721731824. Its totient is φ = 36847146560.

The previous prime is 55281009347. The next prime is 55281009353. The reversal of 55281009351 is 15390018255.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 55281009351 - 22 = 55281009347 is a prime.

It is a super-3 number, since 3×552810093513 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55281009353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1696086 + ... + 1728371.

It is an arithmetic number, because the mean of its divisors is an integer number (9215216478).

Almost surely, 255281009351 is an apocalyptic number.

55281009351 is a deficient number, since it is larger than the sum of its proper divisors (18440722473).

55281009351 is a wasteful number, since it uses less digits than its factorization.

55281009351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3429841.

The product of its (nonzero) digits is 54000, while the sum is 39.

The spelling of 55281009351 in words is "fifty-five billion, two hundred eighty-one million, nine thousand, three hundred fifty-one".

Divisors: 1 3 5381 16143 3424457 10273371 18427003117 55281009351