Base | Representation |
---|---|
bin | 1010010011001110… |
… | …10001101010110011 |
3 | 112021101200002221201 |
4 | 11021213101222303 |
5 | 42311140000201 |
6 | 2312423032031 |
7 | 254016140062 |
oct | 51147215263 |
9 | 15241602851 |
10 | 5530000051 |
11 | 23885a4984 |
12 | 10a3b9b617 |
13 | 6a18b89a4 |
14 | 3a66261d9 |
15 | 225748801 |
hex | 1499d1ab3 |
5530000051 has 2 divisors, whose sum is σ = 5530000052. Its totient is φ = 5530000050.
The previous prime is 5530000043. The next prime is 5530000093. The reversal of 5530000051 is 1500000355.
5530000051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5530000051 - 23 = 5530000043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5529999983 and 5530000028.
It is not a weakly prime, because it can be changed into another prime (5530000031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2765000025 + 2765000026.
It is an arithmetic number, because the mean of its divisors is an integer number (2765000026).
Almost surely, 25530000051 is an apocalyptic number.
5530000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5530000051 is an equidigital number, since it uses as much as digits as its factorization.
5530000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 375, while the sum is 19.
The square root of 5530000051 is about 74363.9701132208. The cubic root of 5530000051 is about 1768.3777630090.
The spelling of 5530000051 in words is "five billion, five hundred thirty million, fifty-one", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •