Base | Representation |
---|---|
bin | 11001001001011100011000… |
… | …01010101100100001011011 |
3 | 21020210122002221201122122011 |
4 | 30210232030022230201123 |
5 | 24222014003210100133 |
6 | 313340254513410351 |
7 | 14435203633320253 |
oct | 1444561412544133 |
9 | 236718087648564 |
10 | 55300055550043 |
11 | 16690692763477 |
12 | 62516308699b7 |
13 | 24b1a07c95495 |
14 | d92773632963 |
15 | 65d7348646cd |
hex | 324b8c2ac85b |
55300055550043 has 2 divisors, whose sum is σ = 55300055550044. Its totient is φ = 55300055550042.
The previous prime is 55300055549953. The next prime is 55300055550073. The reversal of 55300055550043 is 34005555000355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55300055550043 - 213 = 55300055541851 is a prime.
It is a super-2 number, since 2×553000555500432 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55300055549978 and 55300055550005.
It is not a weakly prime, because it can be changed into another prime (55300055550073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27650027775021 + 27650027775022.
It is an arithmetic number, because the mean of its divisors is an integer number (27650027775022).
Almost surely, 255300055550043 is an apocalyptic number.
55300055550043 is a deficient number, since it is larger than the sum of its proper divisors (1).
55300055550043 is an equidigital number, since it uses as much as digits as its factorization.
55300055550043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 562500, while the sum is 40.
The spelling of 55300055550043 in words is "fifty-five trillion, three hundred billion, fifty-five million, five hundred fifty thousand, forty-three".
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