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55310113 is a prime number
BaseRepresentation
bin1101001011111…
…1011100100001
310212002001012201
43102333130201
5103124410423
65253253201
71241061655
oct322773441
9125061181
1055310113
1129248341
1216634201
13b5c73a1
1474baa65
154cc82ad
hex34bf721

55310113 has 2 divisors, whose sum is σ = 55310114. Its totient is φ = 55310112.

The previous prime is 55310071. The next prime is 55310131. The reversal of 55310113 is 31101355.

Together with next prime (55310131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54878464 + 431649 = 7408^2 + 657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55310113 is a prime.

It is not a weakly prime, because it can be changed into another prime (55310183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27655056 + 27655057.

It is an arithmetic number, because the mean of its divisors is an integer number (27655057).

Almost surely, 255310113 is an apocalyptic number.

It is an amenable number.

55310113 is a deficient number, since it is larger than the sum of its proper divisors (1).

55310113 is an equidigital number, since it uses as much as digits as its factorization.

55310113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 55310113 is about 7437.0769123359. The cubic root of 55310113 is about 381.0086614500.

Adding to 55310113 its reverse (31101355), we get a palindrome (86411468).

The spelling of 55310113 in words is "fifty-five million, three hundred ten thousand, one hundred thirteen".