Base | Representation |
---|---|
bin | 101000001111100101110… |
… | …1100110100001101101001 |
3 | 201120202120201101012210102 |
4 | 1100133023230310031221 |
5 | 1211110032322324001 |
6 | 15432531435555145 |
7 | 1110414223651646 |
oct | 120371354641551 |
9 | 21522521335712 |
10 | 5531040433001 |
11 | 1842779148776 |
12 | 753b522bbab5 |
13 | 311761cccc55 |
14 | 1519bd288dcd |
15 | 98d1d499e6b |
hex | 507cbb34369 |
5531040433001 has 2 divisors, whose sum is σ = 5531040433002. Its totient is φ = 5531040433000.
The previous prime is 5531040432989. The next prime is 5531040433007. The reversal of 5531040433001 is 1003340401355.
5531040433001 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4159621435225 + 1371418997776 = 2039515^2 + 1171076^2 .
It is a cyclic number.
It is not a de Polignac number, because 5531040433001 - 214 = 5531040416617 is a prime.
It is not a weakly prime, because it can be changed into another prime (5531040433007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2765520216500 + 2765520216501.
It is an arithmetic number, because the mean of its divisors is an integer number (2765520216501).
Almost surely, 25531040433001 is an apocalyptic number.
It is an amenable number.
5531040433001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5531040433001 is an equidigital number, since it uses as much as digits as its factorization.
5531040433001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 5531040433001 its reverse (1003340401355), we get a palindrome (6534380834356).
The spelling of 5531040433001 in words is "five trillion, five hundred thirty-one billion, forty million, four hundred thirty-three thousand, one".
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