Base | Representation |
---|---|
bin | 111110111000010111110010… |
… | …0111000000101101010111011 |
3 | 2200112101100210122101210021211 |
4 | 1331300233210320011222323 |
5 | 1034444034411412220443 |
6 | 5240205043412343551 |
7 | 224334356153315065 |
oct | 17560574470055273 |
9 | 2615340718353254 |
10 | 553105433320123 |
11 | 150266773753542 |
12 | 5204b656614bb7 |
13 | 1a981806c916c8 |
14 | 9a82635438735 |
15 | 43e281ced919d |
hex | 1f70be4e05abb |
553105433320123 has 2 divisors, whose sum is σ = 553105433320124. Its totient is φ = 553105433320122.
The previous prime is 553105433319949. The next prime is 553105433320127. The reversal of 553105433320123 is 321023334501355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 553105433320123 - 229 = 553104896449211 is a prime.
It is not a weakly prime, because it can be changed into another prime (553105433320127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276552716660061 + 276552716660062.
It is an arithmetic number, because the mean of its divisors is an integer number (276552716660062).
Almost surely, 2553105433320123 is an apocalyptic number.
553105433320123 is a deficient number, since it is larger than the sum of its proper divisors (1).
553105433320123 is an equidigital number, since it uses as much as digits as its factorization.
553105433320123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486000, while the sum is 40.
Adding to 553105433320123 its reverse (321023334501355), we get a palindrome (874128767821478).
The spelling of 553105433320123 in words is "five hundred fifty-three trillion, one hundred five billion, four hundred thirty-three million, three hundred twenty thousand, one hundred twenty-three".
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