Base | Representation |
---|---|
bin | 10000000110010010110… |
… | …00101101110101011001 |
3 | 1221212201220011200000212 |
4 | 20003021120231311121 |
5 | 33030304413412442 |
6 | 1102035000140505 |
7 | 54651121534406 |
oct | 10031130556531 |
9 | 1855656150025 |
10 | 553134513497 |
11 | 1a3646015975 |
12 | 8b24b767735 |
13 | 4021140acc7 |
14 | 1cab3d732ad |
15 | e5c578ca82 |
hex | 80c962dd59 |
553134513497 has 2 divisors, whose sum is σ = 553134513498. Its totient is φ = 553134513496.
The previous prime is 553134513493. The next prime is 553134513517. The reversal of 553134513497 is 794315431355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 497954624281 + 55179889216 = 705659^2 + 234904^2 .
It is a cyclic number.
It is not a de Polignac number, because 553134513497 - 22 = 553134513493 is a prime.
It is not a weakly prime, because it can be changed into another prime (553134513493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276567256748 + 276567256749.
It is an arithmetic number, because the mean of its divisors is an integer number (276567256749).
Almost surely, 2553134513497 is an apocalyptic number.
It is an amenable number.
553134513497 is a deficient number, since it is larger than the sum of its proper divisors (1).
553134513497 is an equidigital number, since it uses as much as digits as its factorization.
553134513497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3402000, while the sum is 50.
The spelling of 553134513497 in words is "five hundred fifty-three billion, one hundred thirty-four million, five hundred thirteen thousand, four hundred ninety-seven".
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