Base | Representation |
---|---|
bin | 11001001001111001011010… |
… | …10101011101101000101001 |
3 | 21020212010100100220121021012 |
4 | 30210330231111131220221 |
5 | 24222242414432000223 |
6 | 313351353424553305 |
7 | 14436265143363644 |
oct | 1444745525355051 |
9 | 236763310817235 |
10 | 55315644406313 |
11 | 16697262211965 |
12 | 6254661482835 |
13 | 24b3320807aa5 |
14 | d93411b3ca5b |
15 | 65dd481e4c78 |
hex | 324f2d55da29 |
55315644406313 has 2 divisors, whose sum is σ = 55315644406314. Its totient is φ = 55315644406312.
The previous prime is 55315644406273. The next prime is 55315644406369. The reversal of 55315644406313 is 31360444651355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54825850184704 + 489794221609 = 7404448^2 + 699853^2 .
It is a cyclic number.
It is not a de Polignac number, because 55315644406313 - 210 = 55315644405289 is a prime.
It is not a weakly prime, because it can be changed into another prime (55315644406213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27657822203156 + 27657822203157.
It is an arithmetic number, because the mean of its divisors is an integer number (27657822203157).
Almost surely, 255315644406313 is an apocalyptic number.
It is an amenable number.
55315644406313 is a deficient number, since it is larger than the sum of its proper divisors (1).
55315644406313 is an equidigital number, since it uses as much as digits as its factorization.
55315644406313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776000, while the sum is 50.
The spelling of 55315644406313 in words is "fifty-five trillion, three hundred fifteen billion, six hundred forty-four million, four hundred six thousand, three hundred thirteen".
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