Base | Representation |
---|---|
bin | 11001001010001011011011… |
… | …00110011110000110101101 |
3 | 21020220001022011012201220102 |
4 | 30211011231212132012231 |
5 | 24222422220002303401 |
6 | 313400033034400445 |
7 | 14440056551231561 |
oct | 1445055546360655 |
9 | 236801264181812 |
10 | 55325312541101 |
11 | 166a03736686a9 |
12 | 62564bb290125 |
13 | 24b420181b4c5 |
14 | d93a8bb956a1 |
15 | 65e211d9c56b |
hex | 32516d99e1ad |
55325312541101 has 16 divisors (see below), whose sum is σ = 57762569040000. Its totient is φ = 52923430074816.
The previous prime is 55325312541097. The next prime is 55325312541131. The reversal of 55325312541101 is 10114521352355.
It is a cyclic number.
It is not a de Polignac number, because 55325312541101 - 22 = 55325312541097 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55325312541131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41123240 + ... + 42447278.
It is an arithmetic number, because the mean of its divisors is an integer number (3610160565000).
Almost surely, 255325312541101 is an apocalyptic number.
It is an amenable number.
55325312541101 is a deficient number, since it is larger than the sum of its proper divisors (2437256498899).
55325312541101 is a wasteful number, since it uses less digits than its factorization.
55325312541101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1337396.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 55325312541101 its reverse (10114521352355), we get a palindrome (65439833893456).
The spelling of 55325312541101 in words is "fifty-five trillion, three hundred twenty-five billion, three hundred twelve million, five hundred forty-one thousand, one hundred one".
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