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55325805528313 is a prime number
BaseRepresentation
bin11001001010001100010101…
…11111000100010011111001
321020220002120111212002020001
430211012022333010103321
524222424222203401223
6313400154005033001
714440105015450225
oct1445061277042371
9236802514762201
1055325805528313
11166a05a6975251
1262566183b5761
1324b427c9b9608
14d93ad7443785
1565e2402cc9ad
hex32518afc44f9

55325805528313 has 2 divisors, whose sum is σ = 55325805528314. Its totient is φ = 55325805528312.

The previous prime is 55325805528277. The next prime is 55325805528319. The reversal of 55325805528313 is 31382550852355.

55325805528313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48224177475769 + 7101628052544 = 6944363^2 + 2664888^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55325805528313 is a prime.

It is not a weakly prime, because it can be changed into another prime (55325805528319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27662902764156 + 27662902764157.

It is an arithmetic number, because the mean of its divisors is an integer number (27662902764157).

Almost surely, 255325805528313 is an apocalyptic number.

It is an amenable number.

55325805528313 is a deficient number, since it is larger than the sum of its proper divisors (1).

55325805528313 is an equidigital number, since it uses as much as digits as its factorization.

55325805528313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600000, while the sum is 55.

The spelling of 55325805528313 in words is "fifty-five trillion, three hundred twenty-five billion, eight hundred five million, five hundred twenty-eight thousand, three hundred thirteen".