Base | Representation |
---|---|
bin | 11001001010001110100100… |
… | …11010111100001101000011 |
3 | 21020220012200001000122021112 |
4 | 30211013102122330031003 |
5 | 24222434201012024400 |
6 | 313400512540513535 |
7 | 14440146510443561 |
oct | 1445072232741503 |
9 | 236805601018245 |
10 | 55327004017475 |
11 | 166a1061439963 |
12 | 62568b184b8ab |
13 | 24b44110a21b8 |
14 | d93bac69ca31 |
15 | 65e2b061a835 |
hex | 3251d26bc343 |
55327004017475 has 24 divisors (see below), whose sum is σ = 69146813606400. Its totient is φ = 43912370315520.
The previous prime is 55327004017471. The next prime is 55327004017477. The reversal of 55327004017475 is 57471040072355.
It is not a de Polignac number, because 55327004017475 - 22 = 55327004017471 is a prime.
It is a super-2 number, since 2×553270040174752 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55327004017471) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 283903169 + ... + 284097981.
It is an arithmetic number, because the mean of its divisors is an integer number (2881117233600).
Almost surely, 255327004017475 is an apocalyptic number.
55327004017475 is a deficient number, since it is larger than the sum of its proper divisors (13819809588925).
55327004017475 is a wasteful number, since it uses less digits than its factorization.
55327004017475 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284399 (or 284394 counting only the distinct ones).
The product of its (nonzero) digits is 4116000, while the sum is 50.
The spelling of 55327004017475 in words is "fifty-five trillion, three hundred twenty-seven billion, four million, seventeen thousand, four hundred seventy-five".
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