Base | Representation |
---|---|
bin | 1010010011100011… |
… | …01111101011010011 |
3 | 112021120211112111101 |
4 | 11021301233223103 |
5 | 42312340310103 |
6 | 2313001525231 |
7 | 254051360104 |
oct | 51161575323 |
9 | 15246745441 |
10 | 5532744403 |
11 | 238a0a983a |
12 | 10a4aa3817 |
13 | 6a2339b74 |
14 | 3a6b3c3ab |
15 | 225adba1d |
hex | 149c6fad3 |
5532744403 has 2 divisors, whose sum is σ = 5532744404. Its totient is φ = 5532744402.
The previous prime is 5532744361. The next prime is 5532744419. The reversal of 5532744403 is 3044472355.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5532744403 is a prime.
It is a super-2 number, since 2×55327444032 = 61222521257855652818, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5532744493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2766372201 + 2766372202.
It is an arithmetic number, because the mean of its divisors is an integer number (2766372202).
Almost surely, 25532744403 is an apocalyptic number.
5532744403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5532744403 is an equidigital number, since it uses as much as digits as its factorization.
5532744403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 37.
The square root of 5532744403 is about 74382.4199861768. The cubic root of 5532744403 is about 1768.6702433240.
The spelling of 5532744403 in words is "five billion, five hundred thirty-two million, seven hundred forty-four thousand, four hundred three".
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