Base | Representation |
---|---|
bin | 11001001010010110101000… |
… | …10011101000011011000011 |
3 | 21020220121211120021222111221 |
4 | 30211023110103220123003 |
5 | 24223022031114420141 |
6 | 313402510135015511 |
7 | 14440361645130421 |
oct | 1445132423503303 |
9 | 236817746258457 |
10 | 55331330623171 |
11 | 166a2981719849 |
12 | 62576ba80a597 |
13 | 24b4950578705 |
14 | d9409d150111 |
15 | 65e4653a7bd1 |
hex | 3252d44e86c3 |
55331330623171 has 2 divisors, whose sum is σ = 55331330623172. Its totient is φ = 55331330623170.
The previous prime is 55331330623103. The next prime is 55331330623201. The reversal of 55331330623171 is 17132603313355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55331330623171 - 27 = 55331330623043 is a prime.
It is a super-2 number, since 2×553313306231712 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55331330623271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27665665311585 + 27665665311586.
It is an arithmetic number, because the mean of its divisors is an integer number (27665665311586).
Almost surely, 255331330623171 is an apocalyptic number.
55331330623171 is a deficient number, since it is larger than the sum of its proper divisors (1).
55331330623171 is an equidigital number, since it uses as much as digits as its factorization.
55331330623171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 510300, while the sum is 43.
The spelling of 55331330623171 in words is "fifty-five trillion, three hundred thirty-one billion, three hundred thirty million, six hundred twenty-three thousand, one hundred seventy-one".
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