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553320052112017 is a prime number
BaseRepresentation
bin111110111001111011101110…
…1001001110011101010010001
32200120010212202210112001021001
41331303313131021303222101
51040011043431320041032
65240451420042102001
7224356024465044451
oct17563673511635221
92616125683461231
10553320052112017
11150339797436433
1252085171aaa901
131a998b1ab678a8
149a8cb94c6bd61
1543e81cea723e7
hex1f73ddd273a91

553320052112017 has 2 divisors, whose sum is σ = 553320052112018. Its totient is φ = 553320052112016.

The previous prime is 553320052111997. The next prime is 553320052112141. The reversal of 553320052112017 is 710211250023355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 488431614039121 + 64888438072896 = 22100489^2 + 8055336^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-553320052112017 is a prime.

It is not a weakly prime, because it can be changed into another prime (553320052112417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276660026056008 + 276660026056009.

It is an arithmetic number, because the mean of its divisors is an integer number (276660026056009).

Almost surely, 2553320052112017 is an apocalyptic number.

It is an amenable number.

553320052112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

553320052112017 is an equidigital number, since it uses as much as digits as its factorization.

553320052112017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 37.

The spelling of 553320052112017 in words is "five hundred fifty-three trillion, three hundred twenty billion, fifty-two million, one hundred twelve thousand, seventeen".