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55333433 is a prime number
BaseRepresentation
bin1101001100010…
…1001000111001
310212010020012102
43103011020321
5103131132213
65253553145
71241216651
oct323051071
9125106172
1055333433
1129263911
12166457b5
13b604b9c
1474c5361
154cd0158
hex34c5239

55333433 has 2 divisors, whose sum is σ = 55333434. Its totient is φ = 55333432.

The previous prime is 55333379. The next prime is 55333441. The reversal of 55333433 is 33433355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49168144 + 6165289 = 7012^2 + 2483^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55333433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55333396 and 55333405.

It is not a weakly prime, because it can be changed into another prime (55333493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27666716 + 27666717.

It is an arithmetic number, because the mean of its divisors is an integer number (27666717).

Almost surely, 255333433 is an apocalyptic number.

It is an amenable number.

55333433 is a deficient number, since it is larger than the sum of its proper divisors (1).

55333433 is an equidigital number, since it uses as much as digits as its factorization.

55333433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24300, while the sum is 29.

The square root of 55333433 is about 7438.6445673926. The cubic root of 55333433 is about 381.0622012283.

Adding to 55333433 its reverse (33433355), we get a palindrome (88766788).

The spelling of 55333433 in words is "fifty-five million, three hundred thirty-three thousand, four hundred thirty-three".