Base | Representation |
---|---|
bin | 11001001010100101100100… |
… | …11000011010110111010011 |
3 | 21020221101112112210000212021 |
4 | 30211102302120122313103 |
5 | 24223134442423400403 |
6 | 313410314055512311 |
7 | 14441064500402323 |
oct | 1445226230326723 |
9 | 236841475700767 |
10 | 55339351387603 |
11 | 166a6318189888 |
12 | 6259178988697 |
13 | 24b562b1abb7a |
14 | d946204a1283 |
15 | 65e7846058bd |
hex | 3254b261add3 |
55339351387603 has 2 divisors, whose sum is σ = 55339351387604. Its totient is φ = 55339351387602.
The previous prime is 55339351387597. The next prime is 55339351387729. The reversal of 55339351387603 is 30678315393355.
55339351387603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55339351387603 - 221 = 55339349290451 is a prime.
It is not a weakly prime, because it can be changed into another prime (55339331387603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27669675693801 + 27669675693802.
It is an arithmetic number, because the mean of its divisors is an integer number (27669675693802).
Almost surely, 255339351387603 is an apocalyptic number.
55339351387603 is a deficient number, since it is larger than the sum of its proper divisors (1).
55339351387603 is an equidigital number, since it uses as much as digits as its factorization.
55339351387603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 91854000, while the sum is 61.
The spelling of 55339351387603 in words is "fifty-five trillion, three hundred thirty-nine billion, three hundred fifty-one million, three hundred eighty-seven thousand, six hundred three".
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