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55341111473 is a prime number
BaseRepresentation
bin110011100010100101…
…100101100010110001
312021211211001202011022
4303202211211202301
51401314311031343
641231240025225
73666255454214
oct634245454261
9167754052138
1055341111473
112151968416a
12a885762215
1352ac491b0b
14296dc2777b
15168d72b568
hexce29658b1

55341111473 has 2 divisors, whose sum is σ = 55341111474. Its totient is φ = 55341111472.

The previous prime is 55341111461. The next prime is 55341111533. The reversal of 55341111473 is 37411114355.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55106623504 + 234487969 = 234748^2 + 15313^2 .

It is a cyclic number.

It is not a de Polignac number, because 55341111473 - 230 = 54267369649 is a prime.

It is not a weakly prime, because it can be changed into another prime (55341141473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27670555736 + 27670555737.

It is an arithmetic number, because the mean of its divisors is an integer number (27670555737).

Almost surely, 255341111473 is an apocalyptic number.

It is an amenable number.

55341111473 is a deficient number, since it is larger than the sum of its proper divisors (1).

55341111473 is an equidigital number, since it uses as much as digits as its factorization.

55341111473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25200, while the sum is 35.

The spelling of 55341111473 in words is "fifty-five billion, three hundred forty-one million, one hundred eleven thousand, four hundred seventy-three".