Base | Representation |
---|---|
bin | 111110111010101100010111… |
… | …1000011100100101000010011 |
3 | 2200120111212101022212002122112 |
4 | 1331311120233003210220103 |
5 | 1040014301341342040103 |
6 | 5241011412531055535 |
7 | 224366413105413134 |
oct | 17565305703445023 |
9 | 2616455338762575 |
10 | 553424505424403 |
11 | 15037a018623a98 |
12 | 520a14631415ab |
13 | 1a9a5926185302 |
14 | 9a93c63523c8b |
15 | 43eac94c26cd8 |
hex | 1f7562f0e4a13 |
553424505424403 has 2 divisors, whose sum is σ = 553424505424404. Its totient is φ = 553424505424402.
The previous prime is 553424505424339. The next prime is 553424505424411. The reversal of 553424505424403 is 304424505424355.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 553424505424403 - 26 = 553424505424339 is a prime.
It is a super-2 number, since 2×5534245054244032 (a number of 30 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (553424505424003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276712252712201 + 276712252712202.
It is an arithmetic number, because the mean of its divisors is an integer number (276712252712202).
Almost surely, 2553424505424403 is an apocalyptic number.
553424505424403 is a deficient number, since it is larger than the sum of its proper divisors (1).
553424505424403 is an equidigital number, since it uses as much as digits as its factorization.
553424505424403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040000, while the sum is 50.
The spelling of 553424505424403 in words is "five hundred fifty-three trillion, four hundred twenty-four billion, five hundred five million, four hundred twenty-four thousand, four hundred three".
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