Base | Representation |
---|---|
bin | 11001001010101110011110… |
… | …01110001010111010010001 |
3 | 21020221211212120222020012020 |
4 | 30211113033032022322101 |
5 | 24223224234313114002 |
6 | 313412424210322053 |
7 | 14441324065606434 |
oct | 1445271716127221 |
9 | 236854776866166 |
10 | 55344130207377 |
11 | 166a834a757910 |
12 | 625a091289329 |
13 | 24b5c10278a8b |
14 | d9495502981b |
15 | 65e963e1c2bc |
hex | 3255cf38ae91 |
55344130207377 has 64 divisors (see below), whose sum is σ = 87666561792000. Its totient is φ = 30678286464000.
The previous prime is 55344130207369. The next prime is 55344130207441. The reversal of 55344130207377 is 77370203144355.
It is not a de Polignac number, because 55344130207377 - 23 = 55344130207369 is a prime.
It is a super-2 number, since 2×553441302073772 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55344130207307) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 234788377 + ... + 235023977.
It is an arithmetic number, because the mean of its divisors is an integer number (1369790028000).
Almost surely, 255344130207377 is an apocalyptic number.
55344130207377 is a gapful number since it is divisible by the number (57) formed by its first and last digit.
It is an amenable number.
55344130207377 is a deficient number, since it is larger than the sum of its proper divisors (32322431584623).
55344130207377 is a wasteful number, since it uses less digits than its factorization.
55344130207377 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248582.
The product of its (nonzero) digits is 7408800, while the sum is 51.
The spelling of 55344130207377 in words is "fifty-five trillion, three hundred forty-four billion, one hundred thirty million, two hundred seven thousand, three hundred seventy-seven".
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