Base | Representation |
---|---|
bin | 11001001010101110011110… |
… | …01110001010111011010001 |
3 | 21020221211212120222020021121 |
4 | 30211113033032022323101 |
5 | 24223224234313114231 |
6 | 313412424210322241 |
7 | 14441324065606555 |
oct | 1445271716127321 |
9 | 236854776866247 |
10 | 55344130207441 |
11 | 166a834a757969 |
12 | 625a091289381 |
13 | 24b5c10278b0a |
14 | d94955029865 |
15 | 65e963e1c311 |
hex | 3255cf38aed1 |
55344130207441 has 2 divisors, whose sum is σ = 55344130207442. Its totient is φ = 55344130207440.
The previous prime is 55344130207369. The next prime is 55344130207463. The reversal of 55344130207441 is 14470203144355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49621528505025 + 5722601702416 = 7044255^2 + 2392196^2 .
It is a cyclic number.
It is not a de Polignac number, because 55344130207441 - 211 = 55344130205393 is a prime.
It is not a weakly prime, because it can be changed into another prime (55344130307441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27672065103720 + 27672065103721.
It is an arithmetic number, because the mean of its divisors is an integer number (27672065103721).
Almost surely, 255344130207441 is an apocalyptic number.
It is an amenable number.
55344130207441 is a deficient number, since it is larger than the sum of its proper divisors (1).
55344130207441 is an equidigital number, since it uses as much as digits as its factorization.
55344130207441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 806400, while the sum is 43.
The spelling of 55344130207441 in words is "fifty-five trillion, three hundred forty-four billion, one hundred thirty million, two hundred seven thousand, four hundred forty-one".
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